3.2.82 \(\int \frac {x^5}{(a+b x)^3} \, dx\) [182]

Optimal. Leaf size=77 \[ \frac {6 a^2 x}{b^5}-\frac {3 a x^2}{2 b^4}+\frac {x^3}{3 b^3}+\frac {a^5}{2 b^6 (a+b x)^2}-\frac {5 a^4}{b^6 (a+b x)}-\frac {10 a^3 \log (a+b x)}{b^6} \]

[Out]

6*a^2*x/b^5-3/2*a*x^2/b^4+1/3*x^3/b^3+1/2*a^5/b^6/(b*x+a)^2-5*a^4/b^6/(b*x+a)-10*a^3*ln(b*x+a)/b^6

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Rubi [A]
time = 0.03, antiderivative size = 77, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {45} \begin {gather*} \frac {a^5}{2 b^6 (a+b x)^2}-\frac {5 a^4}{b^6 (a+b x)}-\frac {10 a^3 \log (a+b x)}{b^6}+\frac {6 a^2 x}{b^5}-\frac {3 a x^2}{2 b^4}+\frac {x^3}{3 b^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^5/(a + b*x)^3,x]

[Out]

(6*a^2*x)/b^5 - (3*a*x^2)/(2*b^4) + x^3/(3*b^3) + a^5/(2*b^6*(a + b*x)^2) - (5*a^4)/(b^6*(a + b*x)) - (10*a^3*
Log[a + b*x])/b^6

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int \frac {x^5}{(a+b x)^3} \, dx &=\int \left (\frac {6 a^2}{b^5}-\frac {3 a x}{b^4}+\frac {x^2}{b^3}-\frac {a^5}{b^5 (a+b x)^3}+\frac {5 a^4}{b^5 (a+b x)^2}-\frac {10 a^3}{b^5 (a+b x)}\right ) \, dx\\ &=\frac {6 a^2 x}{b^5}-\frac {3 a x^2}{2 b^4}+\frac {x^3}{3 b^3}+\frac {a^5}{2 b^6 (a+b x)^2}-\frac {5 a^4}{b^6 (a+b x)}-\frac {10 a^3 \log (a+b x)}{b^6}\\ \end {align*}

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Mathematica [A]
time = 0.01, size = 67, normalized size = 0.87 \begin {gather*} \frac {36 a^2 b x-9 a b^2 x^2+2 b^3 x^3+\frac {3 a^5}{(a+b x)^2}-\frac {30 a^4}{a+b x}-60 a^3 \log (a+b x)}{6 b^6} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^5/(a + b*x)^3,x]

[Out]

(36*a^2*b*x - 9*a*b^2*x^2 + 2*b^3*x^3 + (3*a^5)/(a + b*x)^2 - (30*a^4)/(a + b*x) - 60*a^3*Log[a + b*x])/(6*b^6
)

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Mathics [A]
time = 2.33, size = 116, normalized size = 1.51 \begin {gather*} \frac {-60 a^5 \text {Log}\left [a+b x\right ]-27 a^5-120 a^4 b x \text {Log}\left [a+b x\right ]+6 a^4 b x-60 a^3 b^2 x^2 \text {Log}\left [a+b x\right ]+63 a^3 b^2 x^2+20 a^2 b^3 x^3-5 a b^4 x^4+2 b^5 x^5}{6 b^6 \left (a^2+2 a b x+b^2 x^2\right )} \end {gather*}

Antiderivative was successfully verified.

[In]

mathics('Integrate[x^5/(a + b*x)^3,x]')

[Out]

(-60 a ^ 5 Log[a + b x] - 27 a ^ 5 - 120 a ^ 4 b x Log[a + b x] + 6 a ^ 4 b x - 60 a ^ 3 b ^ 2 x ^ 2 Log[a + b
 x] + 63 a ^ 3 b ^ 2 x ^ 2 + 20 a ^ 2 b ^ 3 x ^ 3 - 5 a b ^ 4 x ^ 4 + 2 b ^ 5 x ^ 5) / (6 b ^ 6 (a ^ 2 + 2 a b
 x + b ^ 2 x ^ 2))

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Maple [A]
time = 0.08, size = 72, normalized size = 0.94

method result size
risch \(\frac {x^{3}}{3 b^{3}}-\frac {3 a \,x^{2}}{2 b^{4}}+\frac {6 a^{2} x}{b^{5}}+\frac {-5 a^{4} x -\frac {9 a^{5}}{2 b}}{b^{5} \left (b x +a \right )^{2}}-\frac {10 a^{3} \ln \left (b x +a \right )}{b^{6}}\) \(68\)
norman \(\frac {\frac {x^{5}}{3 b}-\frac {5 a \,x^{4}}{6 b^{2}}+\frac {10 a^{2} x^{3}}{3 b^{3}}-\frac {15 a^{5}}{b^{6}}-\frac {20 a^{4} x}{b^{5}}}{\left (b x +a \right )^{2}}-\frac {10 a^{3} \ln \left (b x +a \right )}{b^{6}}\) \(70\)
default \(\frac {\frac {1}{3} b^{2} x^{3}-\frac {3}{2} a b \,x^{2}+6 a^{2} x}{b^{5}}-\frac {5 a^{4}}{b^{6} \left (b x +a \right )}+\frac {a^{5}}{2 b^{6} \left (b x +a \right )^{2}}-\frac {10 a^{3} \ln \left (b x +a \right )}{b^{6}}\) \(72\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5/(b*x+a)^3,x,method=_RETURNVERBOSE)

[Out]

1/b^5*(1/3*b^2*x^3-3/2*a*b*x^2+6*a^2*x)-5*a^4/b^6/(b*x+a)+1/2*a^5/b^6/(b*x+a)^2-10*a^3*ln(b*x+a)/b^6

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Maxima [A]
time = 0.27, size = 81, normalized size = 1.05 \begin {gather*} -\frac {10 \, a^{4} b x + 9 \, a^{5}}{2 \, {\left (b^{8} x^{2} + 2 \, a b^{7} x + a^{2} b^{6}\right )}} - \frac {10 \, a^{3} \log \left (b x + a\right )}{b^{6}} + \frac {2 \, b^{2} x^{3} - 9 \, a b x^{2} + 36 \, a^{2} x}{6 \, b^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(b*x+a)^3,x, algorithm="maxima")

[Out]

-1/2*(10*a^4*b*x + 9*a^5)/(b^8*x^2 + 2*a*b^7*x + a^2*b^6) - 10*a^3*log(b*x + a)/b^6 + 1/6*(2*b^2*x^3 - 9*a*b*x
^2 + 36*a^2*x)/b^5

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Fricas [A]
time = 0.31, size = 107, normalized size = 1.39 \begin {gather*} \frac {2 \, b^{5} x^{5} - 5 \, a b^{4} x^{4} + 20 \, a^{2} b^{3} x^{3} + 63 \, a^{3} b^{2} x^{2} + 6 \, a^{4} b x - 27 \, a^{5} - 60 \, {\left (a^{3} b^{2} x^{2} + 2 \, a^{4} b x + a^{5}\right )} \log \left (b x + a\right )}{6 \, {\left (b^{8} x^{2} + 2 \, a b^{7} x + a^{2} b^{6}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(b*x+a)^3,x, algorithm="fricas")

[Out]

1/6*(2*b^5*x^5 - 5*a*b^4*x^4 + 20*a^2*b^3*x^3 + 63*a^3*b^2*x^2 + 6*a^4*b*x - 27*a^5 - 60*(a^3*b^2*x^2 + 2*a^4*
b*x + a^5)*log(b*x + a))/(b^8*x^2 + 2*a*b^7*x + a^2*b^6)

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Sympy [A]
time = 0.16, size = 85, normalized size = 1.10 \begin {gather*} - \frac {10 a^{3} \log {\left (a + b x \right )}}{b^{6}} + \frac {6 a^{2} x}{b^{5}} - \frac {3 a x^{2}}{2 b^{4}} + \frac {- 9 a^{5} - 10 a^{4} b x}{2 a^{2} b^{6} + 4 a b^{7} x + 2 b^{8} x^{2}} + \frac {x^{3}}{3 b^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**5/(b*x+a)**3,x)

[Out]

-10*a**3*log(a + b*x)/b**6 + 6*a**2*x/b**5 - 3*a*x**2/(2*b**4) + (-9*a**5 - 10*a**4*b*x)/(2*a**2*b**6 + 4*a*b*
*7*x + 2*b**8*x**2) + x**3/(3*b**3)

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Giac [A]
time = 0.00, size = 86, normalized size = 1.12 \begin {gather*} \frac {\frac {1}{3} x^{3} b^{6}-\frac {3}{2} x^{2} b^{5} a+6 x b^{4} a^{2}}{b^{9}}+\frac {\frac {1}{2} \left (-10 b a^{4} x-9 a^{5}\right )}{b^{6} \left (x b+a\right )^{2}}-\frac {10 a^{3} \ln \left |x b+a\right |}{b^{6}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(b*x+a)^3,x)

[Out]

-10*a^3*log(abs(b*x + a))/b^6 - 1/2*(10*a^4*b*x + 9*a^5)/((b*x + a)^2*b^6) + 1/6*(2*b^6*x^3 - 9*a*b^5*x^2 + 36
*a^2*b^4*x)/b^9

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Mupad [B]
time = 0.12, size = 67, normalized size = 0.87 \begin {gather*} -\frac {\frac {5\,a\,{\left (a+b\,x\right )}^2}{2}-\frac {{\left (a+b\,x\right )}^3}{3}+\frac {5\,a^4}{a+b\,x}-\frac {a^5}{2\,{\left (a+b\,x\right )}^2}+10\,a^3\,\ln \left (a+b\,x\right )-10\,a^2\,b\,x}{b^6} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5/(a + b*x)^3,x)

[Out]

-((5*a*(a + b*x)^2)/2 - (a + b*x)^3/3 + (5*a^4)/(a + b*x) - a^5/(2*(a + b*x)^2) + 10*a^3*log(a + b*x) - 10*a^2
*b*x)/b^6

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